Question

用C语言写一个产生字符串的随机排列的程序

有一堆字符串，如“26537”“monkey”“USA”“$&”“给我一首歌的时间”。设计一个程序，运行产生上面5个字符串的一个随机排列。

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
char *strs[5] = {"26537", "monkey", "USA", "$&", "给我一首歌的时间"};
char flag[5] = {0};
srand(time(NULL));

for (int i = 0; i < 5; i++)
{
int k;
for (k = rand() % 5; flag[k]; k = rand() % 5)
;
printf("%s", strs[k]);
flag[k] = 1;
}
printf("\n");

}

Answer 2

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void main()
{
int m;
char s1[]="26537";
char s2[]="monkey";
char s3[]="USA";
char s4[]="$&";
char s5[]="给我一首歌的时间";
srand(time(NULL));
m=rand()%5;
switch (m)
{
case 0:
printf("%s\n",s1);
break;
case 1:
printf("%s\n",s2);
break;
case 2:
printf("%s\n",s3);
break;
case 3:
printf("%s\n",s4);
break;
case 4:
printf("%s\n",s5);
break;
default:
break;
}
}

Answer 3

#include <stdlib.h>
#include <stdio.h>
main()
{
char a[5][]={"26537","monkey","USA","$&","给我一首歌的时间"};
int b[5];
randomize();
b[0]=random(5);
while(1)
{randomize();
b[1]=random(5);
if(b[1]!=b[0]) break;}
while(1)
{randomize();
b[2]=random(5);
if((b[2]!=b[0])&&(b[2]!=b[1])) break;
}
while(1)
{
randomize();
b[3]=random(5);
if(b[3]!=b[0])
{if((b[3]!=b[1])&&b[3]!=b[2]) break;}
}
while(1)
{
randomize();
b[4]=random(5);
if((b[4]!=b[0])&&(b[4]!=b[1]))
{if((b[4]!=b[2])&&(b[4]!=b[3])) break;}
}
printf("%s %s %s %s %s\n",a[b[0]],a[b[1]],a[b[2]],a[b[3]],a[b[4]]);
}

Answer 4

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
char *strs[5] = {"26537", "monkey", "USA", "$&", "给我一首歌的时间"};
char flag[5] = {0};
int i=0,j;
srand(time(NULL));
while(i<5)
{
j=rand()%5;
if(flag[j]==0){
printf("%s",strs[j]);
printf("\n");
flag[j]=1;
}
return 0;
}