Question

ios中如何让uibutton内的非矩形区域响应uitouch

Answer 1

举个例子，纯用button是肯定不行的了。比如说一个正方形边长为D,内中心有一个直径也为D的圆，我要求圆内科响应，圆外正方形部分不响应。圆的直径r = D/2.f;

1、给正方形_view添加UITapGestrureRecongnizer *tap

tap.delegate = self;
[_view addGestru...er:tap];

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
CGPoint point = [touch locationInView:_view];

//圆原点坐标为

CGFloat x1 = r;

CGFloat y2 = r;
//

CGFloat x2 = point.x;
CGFloat y2 = point.y;
if((y2-y1)²+(x2-x1)² < r²)

{
//圆内，响应点击

return YES;

}else

{
return NO;

}

}

两点间的距离 d,则 d² = (y2-y1)²+(x2-x1)²;