Question

C语言编程，出现问题，”已停止工作“

代码如下
#include<stdio.h>
int main(void)
{
int num,ten=0,t;

for(t=scanf("%d",num);t!=0;t=scanf("%d",num))
{

for(ten=0;ten<10;ten++,num++)

printf("%d\n",num);

}

}

Answer 1

#include<stdio.h>
int main(void)
{
    int num,ten=0,t;
  for(t=scanf("%d", &num);t!=0;t=scanf("%d", &num))
  {
      for(ten=0;ten<10;ten++,num++)
        printf("%d\n",num);
  }
  return 0;
}

Answer 2

for(t=scanf("%d", &num);t!=0;t=scanf("%d", &num))

scanf()函数，参数中必须是地址类型变量，你少了&

Answer 3

scanf("%d", &num)少了取地址符号

Answer 4

t=scanf("%d",&num),要加写入符号&