打勾的两道题怎么做,急,在线等。微积分,高等数学,基础题求解 20
2个回答
展开全部
2. x = 1-1/(1+t), x'<t> = 1/(1+t)^2,
y = 1+1/t, y'<t> = -1/t^2, z'<t> = 2t
t = 1 时, 切点是 (1/2, 2, 1),
切线向量是 (x'(1), y'(1), z'(1)) = (1/4, -1, 2)
切线方程是 (x-1/2)/(1/4) = (y-2)/(-1) = (z-1)/2
即 (4x-2)/1 =(y-2)/(-1) = (z-1)/2
法平面方程是 (1/4)(x-1/2) -(y-2) +2(z-1) = 0
即 2x-8y+16z-1 = 0
3. F = x^2+y^2-z, F'<x> = 2x, F'<y> = 2y, F'<z> = -1
切点是 (1, 2, 5), 法向量是 (2, 4, -1)
切平面方程 2(x-1)+4(y-2)-(z-5) = 0,
即 2x+4y-z -5 = 0
法线方程 (x-1)/2 = (y-2)/4 = (z-5)/(-1)
y = 1+1/t, y'<t> = -1/t^2, z'<t> = 2t
t = 1 时, 切点是 (1/2, 2, 1),
切线向量是 (x'(1), y'(1), z'(1)) = (1/4, -1, 2)
切线方程是 (x-1/2)/(1/4) = (y-2)/(-1) = (z-1)/2
即 (4x-2)/1 =(y-2)/(-1) = (z-1)/2
法平面方程是 (1/4)(x-1/2) -(y-2) +2(z-1) = 0
即 2x-8y+16z-1 = 0
3. F = x^2+y^2-z, F'<x> = 2x, F'<y> = 2y, F'<z> = -1
切点是 (1, 2, 5), 法向量是 (2, 4, -1)
切平面方程 2(x-1)+4(y-2)-(z-5) = 0,
即 2x+4y-z -5 = 0
法线方程 (x-1)/2 = (y-2)/4 = (z-5)/(-1)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询