
请问5小 题怎么做啊?
2个回答
展开全部
lim(x->9) [x^(1/4) - √3 ]/ (√x - √3) (0/0)
=lim(x->9) (1/4)x^(-3/4)/ [ (1/2)x^(-1/2) ]
=(1/2) lim(x->9) x^(-1/4)
=(1/6)√3
=lim(x->9) (1/4)x^(-3/4)/ [ (1/2)x^(-1/2) ]
=(1/2) lim(x->9) x^(-1/4)
=(1/6)√3
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