Question

高分求用C语言编的闹钟程序或者定时提醒程序300-400行之间

希望哪位帮帮忙
要c语言的 要大于150行的 比如有日期输入，有设置选项（是否输入日期，默认否），再比如有历史记录，使用信息记录等。 谢谢大虾们 暂时还没有满意答案呢···

Answer 1

给，已经编译运行确认了：

#include<conio.h>
#include <stdio.h>

#include<stdlib.h>
#include<time.h>
#include<string.h>
int GetHour(char *s)
{
char *p, *q;
p = (char *)malloc(10);
strcpy(p, s);
q = p;
while(*q != ':')
{
q++;
}
*q = '\0';
return atoi(p);
}

int GetMinute(char *s)
{
char *p;
p = (char *)malloc(10);
strcpy(p, s);
while(*p != ':')
{
p++;
}
p++;
return atoi(p);
}
main()
{
char s[10];
int hour,minute;
time_t t;
struct tm *timeinfo;
printf("please input the time like [18:30]:\n");
gets(s);
hour = GetHour(s);
minute = GetMinute(s);
while(1)
{
time(&t);
timeinfo = localtime(&t);
if(timeinfo->tm_hour < hour)continue;
else if(timeinfo->tm_min < minute)continue;
else
{
printf("Time is up!Wake up!\n\007");
printf("\a\a\a\a");
exit(0);
}
}
}

Answer 2

经调试无误：
#include
#include
#include
#include
#include
void
main()
{
int
gd=DETECT,gm;
int
x=320,y=240,r=200,i,h,m,s,thetamin,thetasec;
struct
time
t;
char
n[12][3]={"3","2","1","12","11","10","9","8","7","6","5","4"};
initgraph(&gd,&gm,"g:\\tc\\bgi");//图形驱动器路径,根据自己的系统更换。
circle(x,y,210);
setcolor(4);
settextstyle(4,0,5);
for(i=0;i<12;i++)
{
if(i!=3)
outtextxy(x+(r-14)*cos(M_PI/6*i)-10,y-(r-14)*sin(M_PI/6*i)-26,n[i]);
else
outtextxy(x+(r-14)*cos(M_PI/6*i)-20,y-(r-14)*sin(M_PI/6*i)-26,n[i]);
}
gettime(&t);
printf("The
current
time
is:
%2d:%02d:%02d.%02d\n",t.ti_hour,
t.ti_min,
t.ti_sec,
t.ti_hund);
while(!kbhit())
{
setcolor(5);
setfillstyle(1,5);
circle(x,y,10);
floodfill(x,y,5);
gettime(&t);
if(t.ti_min!=m)
{
setcolor(0);
line(x,y,x+(r-60)*cos(thetamin*(M_PI/180)),y-(r-60)*sin(thetamin*(M_PI/180
)));
circle(x+(r-80)*cos(thetamin*(M_PI/180)),y-(r-80)*sin(thetamin*(M_PI/180))
,10);
line(x,y,x+(r-110)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-110)*sin(M_PI/6*h
-((m/2)*(M_PI/180))));
circle(x+(r-130)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-130)*sin(M_PI/6*h-(
(m/2)*(M_PI/180))),10);
}
if(t.ti_hour>12)
t.ti_hour=t.ti_hour-12;
if(t.ti_hour<4)
h=abs(t.ti_hour-3);
else&n
bsp;
h=15-t.ti_hour;
m=t.ti_min;
if(t.ti_min<=15)
thetamin=(15-t.ti_min)*6;
else
thetamin=450-t.ti_min*6;
if(t.ti_sec<=15)
thetasec=(15-t.ti_sec)*6;
else
thetasec=450-t.ti_sec*6;
setcolor(4);
line(x,y,x+(r-110)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-110)*sin(M_PI/6*h
-((m/2)*(M_PI/180))));
circle(x+(r-130)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-130)*sin(M_PI/6*h-(
(m/2)*(M_PI/180))),10);
line(x,y,x+(r-60)*cos(thetamin*(M_PI/180)),y-(r-60)*sin(thetamin*(M_PI/180
)));
circle(x+(r-80)*cos(thetamin*(M_PI/180)),y-(r-80)*sin(thetamin*(M_PI/180))
,10);
setcolor(15);
line(x,y,x+(r-70)*cos(thetasec*(M_PI/180)),y-(r-70)*sin(thetasec*(M_PI/180
)));
delay(1000);
setcolor(0);
line(x,y,x+(r-70)*cos(thetasec*(M_PI/180)),y-(r-70)*sin(thetasec*(M_PI/180
)));
}
}

Answer 3

经调试无误：
#include
#include
#include
#include
#include
void main()
{
int gd=DETECT,gm;
int x=320,y=240,r=200,i,h,m,s,thetamin,thetasec;
struct time t;
char n[12][3]={"3","2","1","12","11","10","9","8","7","6","5","4"};
initgraph(&gd,&gm,"g:\\tc\\bgi");//图形驱动器路径,根据自己的系统更换。
circle(x,y,210);
setcolor(4);
settextstyle(4,0,5);
for(i=0;i<12;i++)
{
if(i!=3)
outtextxy(x+(r-14)*cos(M_PI/6*i)-10,y-(r-14)*sin(M_PI/6*i)-26,n[i]);
else
outtextxy(x+(r-14)*cos(M_PI/6*i)-20,y-(r-14)*sin(M_PI/6*i)-26,n[i]);
}
gettime(&t);
printf("The current time is: %2d:%02d:%02d.%02d\n",t.ti_hour, t.ti_min,
t.ti_sec, t.ti_hund);
while(!kbhit())
{
setcolor(5);
setfillstyle(1,5);
circle(x,y,10);
floodfill(x,y,5);
gettime(&t);
if(t.ti_min!=m)
{
setcolor(0);
line(x,y,x+(r-60)*cos(thetamin*(M_PI/180)),y-(r-60)*sin(thetamin*(M_PI/180
)));
circle(x+(r-80)*cos(thetamin*(M_PI/180)),y-(r-80)*sin(thetamin*(M_PI/180))
,10);
line(x,y,x+(r-110)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-110)*sin(M_PI/6*h
-((m/2)*(M_PI/180))));
circle(x+(r-130)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-130)*sin(M_PI/6*h-(
(m/2)*(M_PI/180))),10);
}
if(t.ti_hour>12)
t.ti_hour=t.ti_hour-12;
if(t.ti_hour<4)
h=abs(t.ti_hour-3);
else&n
bsp;
h=15-t.ti_hour;
m=t.ti_min;
if(t.ti_min<=15)
thetamin=(15-t.ti_min)*6;
else
thetamin=450-t.ti_min*6;
if(t.ti_sec<=15)
thetasec=(15-t.ti_sec)*6;
else
thetasec=450-t.ti_sec*6;
setcolor(4);
line(x,y,x+(r-110)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-110)*sin(M_PI/6*h
-((m/2)*(M_PI/180))));
circle(x+(r-130)*cos(M_PI/6*h-((m/2)*(M_PI/180))),y-(r-130)*sin(M_PI/6*h-(
(m/2)*(M_PI/180))),10);
line(x,y,x+(r-60)*cos(thetamin*(M_PI/180)),y-(r-60)*sin(thetamin*(M_PI/180
)));
circle(x+(r-80)*cos(thetamin*(M_PI/180)),y-(r-80)*sin(thetamin*(M_PI/180))
,10);
setcolor(15);
line(x,y,x+(r-70)*cos(thetasec*(M_PI/180)),y-(r-70)*sin(thetasec*(M_PI/180
)));
delay(1000);
setcolor(0);
line(x,y,x+(r-70)*cos(thetasec*(M_PI/180)),y-(r-70)*sin(thetasec*(M_PI/180
)));
}
}

Answer 4

如果他们的回答，你都不满意，我下班的时候，帮你看下吧。现在忙

Answer 5

有那么复杂吗？参与以下linux corn的代码就好了