Question

从键盘上输入10个实数,并求出这十个数所有奇数之和和偶数之和.用c++语言怎样编写？？？

Answer 1

我写是框架吧
#include<iostream.h>
void main()
{
int a[10];
int x,y ;奇数和为X,偶数和为y
for (i=1;i<=10;i++)
{
cin>>a[i];
if(a[i]\2=0) 如果可以被2整除就是偶不能就是奇
{
y=y+a[i];
}
else
{
x=x+a[i];
}

}
cout<<"奇数和为:"<<x<<endl;
cout<<"偶数和为:"<<y<<endl;

}
大至上就是这样的没调试

Answer 2

#include "iostream"
using namespace std;
int main(void)
{
int a[10],i,sum_o=0,sum_e=0;
cout<<"请输入十个数字:";
for(i=0;i<10;i++)
{
cin>>a[i];
if(a[i]%2==0)
sum_e+=a[i];
else
sum_o+=a[i];
}
cout<<"输入的十个数字中所有偶数的和为:"<<sum_e<<endl<<"所有奇数的和为:"<<sum_o<<endl;
return 0;
}

Answer 3

#include<iostream>
using namespace std;
int main()
{
int i,a[10];
int rel1,rel2;
cout<<"输入10个整数："<<endl;
for(i = 0;i < 10;i ++)
cin>>a[i];
rel1=rel2=0;
for(i = 0;i < 10;i ++)
{
if(a[i]%2 == 0) rel1+=a[i];
else rel2+=a[i];
}
cout << "奇数的和是:" << rel2 << endl;
cout << "偶数的和是:" << rel1 <<endl;
return 0;
}

Answer 4

#include <iostream>
using namespace std;

void main()
{
int input[10];
int oldNumber = 0; //奇数和
int evenNumber = 0; //偶数和

cout << " please input ten numbers: " << endl;
for (int i = 0 ; i != 10 ; i ++)
{
cin >> input[i];
if ( (input[i] % 2) == 0)
{
evenNumber += input[i];
}
else
{
oldNumber += input[i];
}
}
cout << "奇数和 ：" << oldNumber;
cout << endl << "偶数和 ：" << evenNumber << endl;

}