已知根号a-1 +(ab-2)^2=0,求(1/ab)+1/(a+1)(b+1) +1/(a+2)(b+2)+``+1/(a+2006)(b+2006)
已知根号a-1+(ab-2)^2=0,求(1/ab)+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2006)(b+2006)...
已知根号a-1 +(ab-2)^2=0,求(1/ab) +1/(a+1)(b+1) +1/(a+2)(b+2)+……+1/(a+2006)(b+2006)
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根号a-1 +(ab-2)^2=0得到a=1,b=2
(1/ab)+1/(a+1)(b+1) +1/(a+2)(b+2)+``+1/(a+2006)(b+2006)
=1/(2*1)+1/(3*2)+……+1/(2008*2007)
=1/1-1/2+1/2-1/3+……+1/2007-1/2008
=1/1-1/2008
=2007/2008.
(1/ab)+1/(a+1)(b+1) +1/(a+2)(b+2)+``+1/(a+2006)(b+2006)
=1/(2*1)+1/(3*2)+……+1/(2008*2007)
=1/1-1/2+1/2-1/3+……+1/2007-1/2008
=1/1-1/2008
=2007/2008.
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