Question

已知a=3+2根号2，b=3-2根号2，求代数式a^b+ab^2的值

Answer 1

a+b=3+2根号2+3-2根号2=6

ab=(3+2根号2)(3-2根号2)
平方差=9-8
=1

所以原式=ab(a+b)
=1*6
=6

Answer 2

a^2b+ab^2的值为6，
解答如下：
a^2b+ab^2
=ab(a+b)
=(3+2√2)(3-2√2)(3+2√2+3-2√2)
=（9-8）x6
=6