Question

C++语言，编写一个把一个三位整数反转的程序，求各位帮忙。

#include<cstdlib>
#include<iostream>
using namespace std;
int main()
{
int a,b;
a>100;
cout<<"请输入一个三位数： ";
cin>>a;

后面的就不知道了。只能有2个变量，且变量是三位数。跪求！

Answer 1

不就是 算个除10的余数 ，可以实测OK

追问

请问是否有三个位数分别加上的？谢谢！

Answer 2

//测试已通过
#include<iostream> 
using namespace std;
int main(){
	int oldNum=123;
	int newNum=0;
	
	while(oldNum>0){
		newNum  = newNum*10 + oldNum%10;
		oldNum /=10; 
	}
	
	cout<<"\nThe new number is: "<<newNum;
	return 0;
}

追问

对不起，我没学过这些词……只学过printf、scanf等词

追答

are you kidding me? This is c++ program .and printf is c program ,ok?

#include<stdio.h> 
int main(){
    int oldNum;
    int newNum=0;
    
     printf("\nInput your num: ");
     scanf("%d",&oldNum);
     
    while(oldNum>0){
        newNum  = newNum*10 + oldNum%10;
        oldNum /=10; 
    }
     
    printf("\nThe new number is:%d ",newNum);
    return 0;
}

追问

C++ just add "#include" to get the letter, do not have a try?

追答

I'm so sorry ,i don't know what are you talking about . but i know my program is right ,so i don't want to do it again, just found someone else to help to solved this problem ,thank you

追问

Not at all

追答

不爽的话,自己来!

Answer 3

#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c,d;
cin>>a;
b=a/100;
c=(a%100)/10;
d=a%10;
cout<<d<<c<<b;
return 0;
}