![](https://iknow-base.cdn.bcebos.com/lxb/notice.png)
1个回答
展开全部
因为 (2x-1)^2+|y+2|=0
所以 2x-1=0 y+2=0
x=1/2 y=-2
3x^2 y+2xy^2+2(xy-2x^2y)-xy+3xy^2
=3x^2y+2xy^2+2xy-4x^2y-xy+3xy^2
=-x^2y+5xy^2+xy
=-(1/2)^2*(-2)+5*(1/2)*(-2)^2+1/2*(-2)
=1/2+5/2-1
=3-1
=2
所以 2x-1=0 y+2=0
x=1/2 y=-2
3x^2 y+2xy^2+2(xy-2x^2y)-xy+3xy^2
=3x^2y+2xy^2+2xy-4x^2y-xy+3xy^2
=-x^2y+5xy^2+xy
=-(1/2)^2*(-2)+5*(1/2)*(-2)^2+1/2*(-2)
=1/2+5/2-1
=3-1
=2
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询