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已知2(x-1/3)²+|y+1|=0,求6x²y-2(x²y-2xy-2x²)-xy的值
已知2(x-1/3)²+|y+1|=0
则x-1/3=0 x=1/3
y+1=0 y=-1
6x²y-2(x²y-2xy-2x²)-xy
=6x²y-2x²y+4xy+4x²-xy
=4x²y+3xy+4x²
=4×1/3²×（-1）+3×1/3×（-1）+4×1/3²
=-4/9-1+4/9
=-1
已知2(x-1/3)²+|y+1|=0
则x-1/3=0 x=1/3
y+1=0 y=-1
6x²y-2(x²y-2xy-2x²)-xy
=6x²y-2x²y+4xy+4x²-xy
=4x²y+3xy+4x²
=4×1/3²×（-1）+3×1/3×（-1）+4×1/3²
=-4/9-1+4/9
=-1
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