Question

求解，要过程，图片，谢谢！

Answer 1

∠AOD:∠BOE=4:1
OE平分∠BOD
∠BOE=DOE
∠AOD:∠BOD=4:2
∠BOD=180°x2/6=60°
∠AOC=∠BOD=60°
OF平分∠COB
∠COF=∠BOF
∠AOF=∠AOC+∠COF=∠AOC+(180°-∠AOC）/2=120°

Answer 2

∵OE平分∠BOD
∴∠BOE=∠DOE
∵∠AOD：∠BOE=4:1
∴∠AOD=4∠BOE
∵∠AOD+∠DOE+∠BOE=180°
∴6∠BOE=180°
∠BOE=30°
∴∠AOD=120°
∴∠AOC=180°-∠AOD=60°
∵OF平分∠COB
∴∠COF=∠FOB
又∠COF+∠FOB+∠BOE+∠DOE=180°
∴∠COF=60°
∴∠AOF=∠AOC+∠COF=60°+60°=120°

Answer 3

分数很低，要求又高这叫求人办事啊同学。