1个回答
展开全部
(x^2+1)^2=x^4 + 2x^2 + 1=(x^5/5 + 2x^3/3 +x)'
所以积分 = x^5/5 + 2x^3/3 +x +C
(1-x)²/√x = (1-2x+x²)/√x = x^(-1/2) -2x^(1/2) +x^(3/2) = ( 2x^(1/2) -4/3 x^(3/2) +2/5 x^(5/2))'
所以积分 = 2x^(1/2) -4/3 x^(3/2) +2/5 x^(5/2) + C
所以积分 = x^5/5 + 2x^3/3 +x +C
(1-x)²/√x = (1-2x+x²)/√x = x^(-1/2) -2x^(1/2) +x^(3/2) = ( 2x^(1/2) -4/3 x^(3/2) +2/5 x^(5/2))'
所以积分 = 2x^(1/2) -4/3 x^(3/2) +2/5 x^(5/2) + C
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
