Question

化简a²+b²+2ab-c²/a²-(b-c)²怎么做

Answer 1

a²+b²+2ab-c²/a²-(b-c)²
=[(a+b)²-c²]/[a²-(b-c)²]
=(a+b+c)(a+b-c)/(a+b-c)(a-b+c)
=(a+b+c)/(a-b+c)