fortran怎么输出矩阵 我的这个怎么回事
DIMENSIONA(5,5)A=(/1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,&17,18,19,20,21,22,23,24,25...
DIMENSION A(5,5)
A=(/1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,
& 17,18,19,20,21 , 22,23,24,25/)
WRITE(*,1) A
1 FORMAT (1X,'A=',5F6.2/2(5X,3F6.2/))
END 展开
A=(/1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,
& 17,18,19,20,21 , 22,23,24,25/)
WRITE(*,1) A
1 FORMAT (1X,'A=',5F6.2/2(5X,3F6.2/))
END 展开
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DIMENSION A(5,5)
data A/1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,&
17,18,19,20,21,22,23,24,25/
WRITE(*,1),A
1 FORMAT (2X,'A=',5F6.2/2(4X,5F6.2/))
END
DIMENSION A(5,5)
data A/1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,&
17,18,19,20,21,22,23,24,25/
WRITE(*,1),A
1 FORMAT (2X,'A=',5F6.2/2(4X,5F6.2/))
END
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