Question

(7-x)+(2√2)²=(½x)²怎么算？

Answer 1

解：7-x+8=x²/4
x²+4x-60=0
（x+10）（x-6）=0
x+10=0或x-6=0
所以x1=-10，x2=6

Answer 2

(7-x)+(2√2)^2=[(1/2)x]^2
7-x+8=(1/4)x^2
4(15-x)=x^2
x^2+4x-60=0
(x+2)^2 =64
x+2 =8 or -8
x=-6 or -10