Question

建立一个复数类，解C++题

建立一个复数类imaginary，其私有数据成员x和y表示复数的实部和虚部，构造函数imaginary用于对复数的实部和虚部初始化，友员函数add，sub，mul，div分别用于进行复数的加，减，乘和除运算，静态函数show用于现实运算结果。在主函数中，实例化两个复数，并输入一个运算符，按运算符选择相应的友员函数进行复数运算，然后输出运算结果。

Answer 1

#include<iostream.h>
class imaginary
{
public:
imaginary(double real,double image)
{
x = real;
y = image;
}
friend imaginary add(double x1,double y1,double x2,double y2);
friend imaginary sub(double x1,double y1,double x2,double y2);
friend imaginary mul(double x1,double y1,double x2,double y2);
friend imaginary div(double x1,double y1,double x2,double y2);
static void show(double x1,double y1,double x2,double y2,char op)
{
switch(op)
{
case '+':
cout<<"两数相加结果为:"<<add(x1,y1,x2,y2).x<<" + "<<add(x1,y1,x2,y2).y<<"i"<<endl;
break;
case '-':
cout<<"两数相减结果为:"<<sub(x1,y1,x2,y2).x<<" + "<<sub(x1,y1,x2,y2).y<<"i"<<endl;
break;
case '*':
cout<<"两数相乘结果为:"<<mul(x1,y1,x2,y2).x<<" + "<<mul(x1,y1,x2,y2).y<<"i"<<endl;
break;
case '/':
cout<<"两数相除结果为:"<<div(x1,y1,x2,y2).x<<" + "<<div(x1,y1,x2,y2).y<<"i"<<endl;
break;
default:
cout<<"输入错误."<<endl;
}
}
private:
double x,y;
};
imaginary add(double x1,double y1,double x2,double y2)
{
double x = x1 + x2;
double y = y1 + y2;
return imaginary(x,y);
}
imaginary sub(double x1,double y1,double x2,double y2)
{
double x = x1 - x2;
double y = y1 - y2;
return imaginary(x,y);
}
imaginary mul(double x1,double y1,double x2,double y2)
{
double x = x1 * x2 - y1 * y2;
double y = x1 * y2 + x2 * y1;
return imaginary(x,y);
}
imaginary div(double x1,double y1,double x2,double y2)
{
double x = (x1 * x2 + y1 * y2)/(x1 * x1 + x2 * x2);
double y = (x2 * y1 - x1 * y2)/(x1 * x1 + x2 * x2);
return imaginary(x,y);
}
void main()
{
double x1,y1,x2,y2;
char op;
cout<<"第一个复数：\n实部：";
cin>>x1;
cout<<"虚部：";
cin>>y1;
cout<<"第二个复数：\n实部：";
cin>>x2;
cout<<"虚部：";
cin>>y2;
cout<<"选择运算：";
cin>>op;
imaginary::show(x1,y1,x2,y2,op);
}

Answer 2

#include
class
imaginary
{
public:
imaginary(double
real,double
image)
{
x
=
real;
y
=
image;
}
friend
imaginary
add(double
x1,double
y1,double
x2,double
y2);
friend
imaginary
sub(double
x1,double
y1,double
x2,double
y2);
friend
imaginary
mul(double
x1,double
y1,double
x2,double
y2);
friend
imaginary
div(double
x1,double
y1,double
x2,double
y2);
static
void
show(double
x1,double
y1,double
x2,double
y2,char
op)
{
switch(op)
{
case
'+':
cout<<"两数相加结果为:"<
>x1;
cout<<"虚部：";
cin>>y1;
cout<<"第二个复数：\n实部：";
cin>>x2;
cout<<"虚部：";
cin>>y2;
cout<<"选择运算：";
cin>>op;
imaginary::show(x1,y1,x2,y2,op);
}