求2.9x0.45+0.29x4.2+0.029x13
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2.9×0.45+0.29×4.2+0.029×13
=2.9×0.45+0.29×10×0.42+0.029×100×0.13
=2.9×0.45+2.9×0.42+2.9×0.13
=2.9×(0.45+0.42+0.13)
=2.9×(0.87+0.13)
=2.9×1
=2.9
=2.9×0.45+0.29×10×0.42+0.029×100×0.13
=2.9×0.45+2.9×0.42+2.9×0.13
=2.9×(0.45+0.42+0.13)
=2.9×(0.87+0.13)
=2.9×1
=2.9
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2.9×0.45+0.29×4.2+0.029×13
=2.9×0.45 + 2.9×0.42 + 2.9×0.13 ............根据积不变的性质改写
=2.9 ×(0.45+0.42+0.13) ......乘法的分配律合并
=2.9×1
=2.9
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2.9x0.45+0.29x4.2+0.029x13
=2.9×0.45+2.9×0.1×4.2+2.9×0.01×13
=2.9×(0.45+0.42+0.13)
=2.9×1
=2.9
=2.9×0.45+2.9×0.1×4.2+2.9×0.01×13
=2.9×(0.45+0.42+0.13)
=2.9×1
=2.9
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