Question

lingo 求和p=xi*yi*C

model:
sets:
x/x1..x6/:a;
y/y1..y6/:b;
m(x,y):d;
endsets

data:
a=1 2 3 4 5 6;
b=2 2 2 2 2 2;
enddata
s=100/@sum(m(J,J):a(J)*b(J));
end

这个得出s后，要再得p=xi*yi*s 该怎么写啊

新手只有25分全给了。
另：有没有关于lingo@for,@sum,线性规划建模详细的教程学习一下，谢谢。

Answer 1

model:
sets:
x/x1..x6/:a,b;
endsets
data:
a=1 2 3 4 5 6;
b=2 2 2 2 2 2;
enddata
calc:
s=100/@sum(x(j):a(J)*b(J));
endcalc
end
Feasible solution found.
Total solver iterations: 0

Variable Value
S 2.380952
A( X1) 1.000000
A( X2) 2.000000
A( X3) 3.000000
A( X4) 4.000000
A( X5) 5.000000
A( X6) 6.000000
B( X1) 2.000000
B( X2) 2.000000
B( X3) 2.000000
B( X4) 2.000000
B( X5) 2.000000
B( X6) 2.000000
model:
sets:
x/x1..x6/:a,b;
endsets
data:
a=1 2 3 4 5 6;
b=2 2 2 2 2 2;
enddata
s=100/@sum(x(j):a(J)*b(J));
end
Feasible solution found.
Total solver iterations: 0

Variable Value
S 2.380952
A( X1) 1.000000
A( X2) 2.000000
A( X3) 3.000000
A( X4) 4.000000
A( X5) 5.000000
A( X6) 6.000000
B( X1) 2.000000
B( X2) 2.000000
B( X3) 2.000000
B( X4) 2.000000
B( X5) 2.000000
B( X6) 2.000000

Row Slack or Surplus
1 0.000000