Question

求助C语言程序题

要求输入一个千万一下的正整数 然后输出为万千百十那种的
例如 输入 12340678
输出就是 1234万6百7十8

Answer 1

自己加个判断0不输出
#include<stdio.h>
main(void)
{
long num,a,b,c,d,e;
scanf("%ld",&num);
if(num>999999&&num<10000000)
{
a=num/10000;
b=(num-a*10000)/1000;
c=(num-a*10000-b*1000)/100;
d=(num%100/10);
e=num%10;
printf("%d,%d,%d,%d,%d",a,b,c,d,e);
}
else if(num>99999)
{
a=num/10000;
b=(num-a*10000)/1000;
c=(num-b*1000-a*10000)/100;
d=(num%100/10);
e=num%10;
}
else if(num>9999)
{
a=num/10000;
b=(num-a*10000)/1000;
c=(num-a*10000-b*1000)/100;
d=(num%100/10);
e=num%10;
}
else if(num>999)
{
a=num/1000;
b=(num-a*1000)/100;
c=(num%100)/10;
d=num%10;
}
else if(num>99)
{
a=num/100;
b=num%10;
}
else
{
a=num;
}
}

Answer 2

#include<stdio.h>
void main()
{
printf("input the data:\n");
long num;
scanf("%d",&num);
int a[5];
a[0]=num%10;
a[1]=num/10%10;
a[2]=num/100%10;
a[3]=num/1000%10;
a[4]=num/10000;
if(a[4]!=0)
printf("%d万",a[4]);
if(a[3]!=0)
printf("%d千",a[3]);
if(a[2]!=0)
printf("%d百",a[2]);
if(a[1]!=0)
printf("%d十",a[1]);
if(a[0]!=0)
printf("%d\n",a[0]);
}