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1)∠AOC+∠BOD
=(∠AOB+∠BOC)+(∠BOC+∠COD)
=(∠AOB+∠COD)+2∠BOC
=50°+2∠BOC
=110°
∠BOC=(110°-50°)/2=30°
∠AOD=∠AOB+∠BOC+∠COD
=(∠AOB+∠COD)+∠BOC
=50°+30°
=80°
2)∠MON=∠MOB+∠BOC∠+∠CON
=(∠MOB+∠CON)+∠BOC
=(∠AOB/2+∠COD/2)+∠BOC
=(∠AOB+∠COD)/2+∠BOC
=50°/2+∠BOC
=25°+30°
=55°
∴∠MON度数保持不变。
即:结论②正确。
=(∠AOB+∠BOC)+(∠BOC+∠COD)
=(∠AOB+∠COD)+2∠BOC
=50°+2∠BOC
=110°
∠BOC=(110°-50°)/2=30°
∠AOD=∠AOB+∠BOC+∠COD
=(∠AOB+∠COD)+∠BOC
=50°+30°
=80°
2)∠MON=∠MOB+∠BOC∠+∠CON
=(∠MOB+∠CON)+∠BOC
=(∠AOB/2+∠COD/2)+∠BOC
=(∠AOB+∠COD)/2+∠BOC
=50°/2+∠BOC
=25°+30°
=55°
∴∠MON度数保持不变。
即:结论②正确。
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