Question

ASP.NET解析JSON 字符串

请问用 Newtonsoft.Json 如何解析如下JSON字符串各属性的值？
如：serial_number ?
field_1?
created_at ? (时间)
谢谢， 求大神
这样的JSON字符串没有[] 包起来，仔细看看，还是不知道怎么解析,希望方便的话提供一个源码DEMO
{
"form": "RTPppE",
"entry": {
"serial_number": 22,
"field_1": "2014-09-25",
"field_13": "华东区",
"field_14": "xxxx",
"field_15": "xxxxxx",
"field_16": 1,
"field_17": 0,
"field_18": 698,
"field_19": "",
"x_field_weixin_nickname": "",
"x_field_weixin_gender": "",
"x_field_weixin_country": "",
"x_field_weixin_province_city": {},
"x_field_weixin_openid": "oFBGBx6kdOI",
"x_field_weixin_headimgurl": "",
"creator_name": "",
"created_at": "2014-09-25T04:06:07Z",
"updated_at": "2014-09-25T04:06:07Z"
}
}

"form": "TyGOun",
"entry": {
"serial_number": 10,
"field_21": "销售",
"field_22": "2014-09-25",
"field_23": {
"level_1": "xxxx",
"level_2": " 01000"
},
"field_24": 1,
"field_25": 798,
"field_26": "",
"field_27": "",
"x_field_weixin_nickname": "",
"x_field_weixin_gender": "",
"x_field_weixin_country": "",
"x_field_weixin_province_city": {},
"x_field_weixin_openid": "",
"x_field_weixin_headimgurl": "",
"creator_name": "",
"created_at": "2014-09-25T07:13:06Z",
"updated_at": "2014-09-25T07:13:06Z"
}
}

Answer 1

创建一个类 Test 属性form 属性entry 对象

entry对象：属性serial_number 属性...

就是这个样子，根据需求来进行解析

Answer 2

你加一个 [], 包起来不就能解析成 List 了

 /// <summary>
        /// 转换为JSON字符串
        /// </summary>
        public static string JsonSerializeByNewton<T>(T obj)
        {
            if (obj == null)
                return "";
            StringWriter sw = new StringWriter(System.Globalization.CultureInfo.InvariantCulture);
            Newtonsoft.Json.JsonSerializer json = new Newtonsoft.Json.JsonSerializer();
            json.NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore;
            json.ReferenceLoopHandling = Newtonsoft.Json.ReferenceLoopHandling.Ignore;
            using (Newtonsoft.Json.JsonWriter jw = new Newtonsoft.Json.JsonTextWriter(sw))
            {
                json.Serialize(jw, obj);
            }
            return sw.ToString();
        }

        public static T JsonDeserializeByNewton<T>(string jsonStr) where T : class
        {
            Newtonsoft.Json.JsonSerializer jSeri = new Newtonsoft.Json.JsonSerializer();
            using (StringReader sr = new StringReader(jsonStr))
            {
                return (T)jSeri.Deserialize(sr, typeof(T));
            }
        }

Answer 3

把字符串转成json对象

$.parseJSON