初二计算题求解，过程
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(x+y)/(√x+√y)+2xy/(x√y+y√x)
=(x+y)(√x-√y)/(x-y)+2xy(x√y-y√x)/(x^2y-y^2x)= (x√x+y√x-x√y-y√y)/(x-y)+2xy(x√y-y√x)/[xy(x-y)]
= (x√x+y√x-x√y-y√y)/(x-y)+2(x√y-y√x)/(x-y)
=(x√x+y√x-x√y-y√y+2x√y-2y√x)/(x-y)
=(x√x-y√x+x√y-y√y)/(x-y)=(x-y)(√x+√y)/(x-y)
=√x+√y
=(x+y)(√x-√y)/(x-y)+2xy(x√y-y√x)/(x^2y-y^2x)= (x√x+y√x-x√y-y√y)/(x-y)+2xy(x√y-y√x)/[xy(x-y)]
= (x√x+y√x-x√y-y√y)/(x-y)+2(x√y-y√x)/(x-y)
=(x√x+y√x-x√y-y√y+2x√y-2y√x)/(x-y)
=(x√x-y√x+x√y-y√y)/(x-y)=(x-y)(√x+√y)/(x-y)
=√x+√y
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