Question

6423怎么算等于24,不能打乱顺序

Answer 1

顺序不变的
(6＋4—2)×3=24
(6＋4÷2)×3=24
(6＋4—2)×3=24
6＋(4＋2)×3=24
(6＋4÷2)×3=24
6＋(4＋2)×3=24
6＋(4＋2)×3=24
6＋(4＋2)×3=24
6＋(4＋2)×3=24
6＋(4＋2)×3=24
(6＋4—2)×3=24
(6＋4—2)×3=24
6＋(4＋2)×3=24
6＋(4＋2)×3=24
6＋(4＋2)×3=24
(6＋4—2)×3=24
(6＋4÷2)×3=24
6＋(4＋2)×3=24

((6+4)-2)*3
(6+(4-2))*3
6+((4+2)*3)
(6+(4/2))*3
6*(4/(3-2))
(6*4)/(3-2)
6*(4*(3-2))
(6*4)*(3-2)
(6-(2-4))*3
((6-2)+4)*3
6+((2+4)*3)
((6*2)-4)*3
(6*2)+(4*3)
((6/2)+3)*4
(6*2)+(3*4)
((6-3)*4)*2
(6-3)*(4*2)
6+(3*(4+2))
((6*3)+4)+2
(6*3)+(4+2)
((6-3)*2)*4
(6-3)*(2*4)
6+(3*(2+4))
6/((3-2)/4)
(6/(3-2))*4
6*((3-2)*4)
(6*(3-2))*4
((6*3)+2)+4
(6*3)+(2+4)
((4+6)-2)*3
(4+(6-2))*3
4*((6/2)+3)
4+((6*3)+2)
(4+(6*3))+2
4*((6-3)*2)
(4*(6-3))*2
4*(6/(3-2))
(4*6)/(3-2)
4*(6*(3-2))
(4*6)*(3-2)
(4-(2-6))*3
((4-2)+6)*3
4+(2+(6*3))
(4+2)+(6*3)
((4/2)+6)*3
4*(2*(6-3))
(4*2)*(6-3)
4+(2+(3*6))
(4+2)+(3*6)
((4+2)*3)+6
4+((3*6)+2)
(4+(3*6))+2
4*(3+(6/2))
(4*3)+(6*2)
4/((3-2)/6)
(4/(3-2))*6
4*((3-2)*6)
(4*(3-2))*6
(4*3)+(2*6)
((2*6)-4)*3
(2*6)+(4*3)
2+((6*3)+4)
(2+(6*3))+4
2*((6-3)*4)
(2*(6-3))*4
(2*6)+(3*4)
2+(4+(6*3))
(2+4)+(6*3)
2*(4*(6-3))
(2*4)*(6-3)
2+(4+(3*6))
(2+4)+(3*6)
((2+4)*3)+6
2+((3*6)+4)
(2+(3*6))+4
3*((6+4)-2)
3*(6+(4-2))
((3*6)+4)+2
(3*6)+(4+2)
3*(6+(4/2))
(3+(6/2))*4
3*(6-(2-4))
3*((6-2)+4)
((3*6)+2)+4
(3*6)+(2+4)
3*((6*2)-4)
3*((4+6)-2)
3*(4+(6-2))
(3*4)+(6*2)
3*(4-(2-6))
3*((4-2)+6)
(3*(4+2))+6
(3*4)+(2*6)
3*((4/2)+6)
((3-2)*6)*4
(3-2)*(6*4)
3*((2*6)-4)
((3-2)*4)*6
(3-2)*(4*6)
(3*(2+4))+6
----END----

追答

经济数学团队为你解答，满意请采纳，谢谢！

Answer 2

(6+4-2)x3

望采纳！！！

Answer 3

(6+4-2)*3=24