Question

java编写程序，输出满足1+2+3+...+n＜8888的最大正整数n。

Answer 1

public static void main(String[] args) {

boolean flag = true;
int n = 0;
int t = 0;
while(flag){
t += n+1;
if(t>=8888){
flag = false;
}
n++;
}
System.out.println("===="+n);
}

Answer 2

public static void main(String[] args) {
int temp=0;
for(int i=1;i<8888;i++) {
if((i*(i+1))/2>=8888) {
System.out.println("满足1+2+3+.....+n<8888的最大正整数为："+temp);
break;
}
temp=i;
}
}

Answer 3

int n=1;
while(n<8888){
n=n+1;
}