一道数学题,求解析,谢谢,刚教不久,不太懂,在线等
2个回答
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an=(2n-3)/(2n+1)*a(n-1)
=(2n-3)/(2n+1)*(2n-5)/(2n-1)*a(n-2)
=(2n-3)/(2n+1)*(2n-5)/(2n-1)*(2n-7)/(2n-3)*a(n-3)
=......
=(2n-3)/(2n+1)*(2n-5)/(2n-1)*(2n-7)/(2n-3)*...*(5/9)*(3/7)*(1/5)*a1
=(3*1)/(2n+1)(2n-1)*1
=3/(4n^2-1)
=(2n-3)/(2n+1)*(2n-5)/(2n-1)*a(n-2)
=(2n-3)/(2n+1)*(2n-5)/(2n-1)*(2n-7)/(2n-3)*a(n-3)
=......
=(2n-3)/(2n+1)*(2n-5)/(2n-1)*(2n-7)/(2n-3)*...*(5/9)*(3/7)*(1/5)*a1
=(3*1)/(2n+1)(2n-1)*1
=3/(4n^2-1)
追问
等等哈,我缓缓
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