留学专业英语数学题
2016-12-29
在等差数列中,设前n项和为Sn,则Sm,S2m-Sm,S3m-S2m也是等差数列。
由题由S20=a,S40-S20=b,则S60-S40=b+(b-a),S80-S60=b+2(b-a)
S100-S80=b+3(b-a),所以S100=10b-5a
原式左边=n!/[(r-1)!*(n-r+1)!] +2(n!)/[r!*(n-r)!]+n!/[(r+1)!*(n-r-1)!]
={[r*(r+1)+2(r+1)*(n-r+1)+(n-r)(n-r+1)]*n!}/(r+1)!*(n-r+1)!
=[(n+1)*(r+1)+(n+1)(n-r+1)]*n!/(r+1)!*(n-r+1)!
=(n+2)!/(r+1)!*(n-r+1)!
=右边
(1)1/sinθ -sinθ=(1-sinθ^2)/sinθ=cosθ^2/sinθ=cosθ/tanθ
(2) (1-sinθ)/cosθ
=(1-sinθ)*(1+sinθ)/[cosθ*(1+sinθ)]=(1-sinθ^2)/[cosθ*(1+sinθ)]
=cosθ^2/[cosθ*(1+sinθ)]=cosθ/1+sinθ
(3)tanθ+1/tanθ=sinθ/cosθ + cosθ/sinθ =(sinθ^2+cosθ^2)/(sinθ *cosθ)=1/(sinθ*cosθ)
(4)(1-2sinθ^2)/(sinθ+cosθ)=(cosθ^2-sinθ^2)/(sinθ+cosθ)=cosθ- sinθ