Question

编一个程序，输入单精度型一维数组a[10]，计算并输出a数组中所有元素的平均值

Answer 1

#include<stdio.h>
int main()
{ float a[10],average,sum=0;
int i;
printf("Please write down array one by one:\n");
for(i=0;i<10;i++)
{ scanf("%f",&a[i]);
sum+=a[i];
}
average=sum/10;
printf("%f",average);
return 0;
}

Answer 2

#include "stdafx.h"
#include"iostream.h"
void main()
{
float a[10],sum=0;
double ave;
cout<<"please input 10 numbers:\n";
for(int i=0;i<10;i++)
{
cin>>a[i];
sum+=a[i];
}
ave=sum/10.0;
cout<<ave<<endl;
}
int/int，意味着取整；