问几个物理问题电学方面的

1.(CanonicalForms)Considerthefunction:f(A,B,C,D)=∑m(0,1,2,7,8,9,10,15)(a)Writethisasa... 1. (Canonical Forms) Consider the function: f (A,B,C,D) =∑m(0,1,2,7,8,9,10,15)
(a) Write this as a Boolean expression in canonical minterm form.
(b) Rewrite the expression in canonical maxterm form.
(c) Write the complement of f in “little m ” notation and as a canonical minterm
expression.
(d) Write the complement of f in “big M ” notation and as a canonical mexterm
expression.
2. (Boolean Simplification) Using K-maps, find the following:
(a) Minimum sum-of-products form for the function and its complement given in
this HW No. 1.
(b) Minimum product-of-sums form for the function and its complement given in
this HW No. 1.
3. (Boolean Simplification) Use K-maps and Boolean equality to simplify the
following functions in the sum-of-products form. How many literals appear in
your minimized solutions?
(a) f (X ,Y,Z) =∏M(0,1,6,7)
(b) f (W, X ,Y,Z) =∏M(1,3,7,9,11,15)
(c) f (A,B,C,D) =∑m(0,2,4,6)
4. (Boolean Simplification) Determine the minimized realization of the following
functions in the sum-of-products form:
(a) f (W, X ,Y,Z) =∑m(0,2,8,9) +∑d(1,3)
(b) f (W, X ,Y,Z) =∑m(1,7,11,13) +∑d(0,5,10,15)
(c) f (A,B,C,D) =∑m(1,2,11,13,14,15) +∑d(0,3,6,10)
(d) f (A,B,C,D) =∏M(2,5,6,8,9,10) ∗∏D(4,11,12)
5. (Laws and Theorems of Boolean Algebra) Simplify the following expressions using
the laws and theorems of Boolean algebra:
(a) W(A,B,C) = ABC + ABC + ABC + ABC
(b) X (A,B,C) = ABC + ABC + ABC + ABC
(c) Y(A,B,C,D) = ABCD + ABCD + ABCD + ABCD + ABCD + ABCD
6. Use K-maps on the expressions of this HW No. 5. Show your work in K-map form.
(a) Find the minimized sum-of-products form.
(b) Find the minimized product-of-sums form.
(c) Find the minimized sum-of-products form of the function’s complement.
(d) Find the minimized product-or-sums form of the functions complement.
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bingo999
2009-04-20 · TA获得超过244个赞
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这是数字逻辑,不是电学。题目很简单啊,让你在和之集(product of sums)与集之和(sum of products)间转化,用卡诺图化简。。。
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匿名用户
2009-04-25
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1 (a)F=A'B'C'D'+A'B'C'D+A'B'CD'+A'BCD+AB'C'D'+AB'C'D+AB'CD'+ABCD
(b)F=````````
嗯···他叫你写标准式,太长了 看不下去了·
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