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第8题好像是这样的吧！
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(1) ∫dx/(2-5x) = (-1/5)∫d(2-5x)/(2-5x) = - (1/5)ln|2-5x| + C
(3) 令 u = √(1-2y)， 则 y = (1-u^2)/2, dy = -udu
∫dy/√(1-2y) = ∫-du = -u + C = -√(1-2y) + C
(5) ∫xdx/(1+x^2) = (1/2)∫d(1+x^2)/(1+x^2) = (1/2)ln(1+x^2) + C
(9) ∫a^(1-3x)dx = (-1/3)∫a^(1-3x)d(1-3x) = (-1/3)a^(1-3x)/lna
(8) ∫x^2dx/(x^3-5)^(2/3) = (1/3)∫d(x^3-5)/(x^3-5)^(2/3)
= (1/3)∫(x^3-5)^(-2/3)d(x^3-5) = (1/3)*3(x^3-5)^(1/3) + C
= (x^3-5)^(1/3) + C
(3) 令 u = √(1-2y)， 则 y = (1-u^2)/2, dy = -udu
∫dy/√(1-2y) = ∫-du = -u + C = -√(1-2y) + C
(5) ∫xdx/(1+x^2) = (1/2)∫d(1+x^2)/(1+x^2) = (1/2)ln(1+x^2) + C
(9) ∫a^(1-3x)dx = (-1/3)∫a^(1-3x)d(1-3x) = (-1/3)a^(1-3x)/lna
(8) ∫x^2dx/(x^3-5)^(2/3) = (1/3)∫d(x^3-5)/(x^3-5)^(2/3)
= (1/3)∫(x^3-5)^(-2/3)d(x^3-5) = (1/3)*3(x^3-5)^(1/3) + C
= (x^3-5)^(1/3) + C
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