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f(x)
= x/(2-x)
=-1 + 2/(2-x) =>f(1) = 1
f'(x) = 2/(2-x)^2 =>f'(1)/1! = 2
f''(x) =2[2!/(2-x)^3] =>f''(1)/2! = 2
f^(n)(x) =2. n!/(2-x)^(n+1) => f^(n)(1)/n! =2
x/(2-x)
=1 +2(x-1) +2(x-1)^2 +....+2(x-1)^n +.....
= x/(2-x)
=-1 + 2/(2-x) =>f(1) = 1
f'(x) = 2/(2-x)^2 =>f'(1)/1! = 2
f''(x) =2[2!/(2-x)^3] =>f''(1)/2! = 2
f^(n)(x) =2. n!/(2-x)^(n+1) => f^(n)(1)/n! =2
x/(2-x)
=1 +2(x-1) +2(x-1)^2 +....+2(x-1)^n +.....
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