Question

已知x+y+z=0,x^3+y＾3+z＾3=0,则xyz=?

Answer 1

x+y+z=0,从而（x+y+z）^3=0,即x^3+y＾3+z＾3+2(y+z)*x^2+2(x+z)*y^2+2(x+y)*z^2+4xyz=0;
因为x+y+z=0,故y+z=-x,x+y=-z,x+z=-y,因此得xyz=0