Question

解方程x(32-x)=120？

Answer 1

x^2-32x+120=0

x1=(-(-32)+√((-32)^2-4*1*120))/(2*1)

=(32+√544)/2

=16+2√34

≈27.661903789690600941748305755091

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x2=(-(-32)-√((-32)^2-4*1*120))/(2*1)

=(32-√544)/2

=16-2√34

≈4.3380962103093990582516942449088

Answer 2

x（32-x）=120
32x-x²=120
x²-32x+120=0
（x-16）²=16²-120
（x-16）²=136
x-16=±√136
x1=16+2√34
x2=16-2√34