Question

用四种方法编程实现对输入的两个数进行交换(c++)

Answer 1

1
swap(int *p1,int *p2)
{int temp;
temp=*p1;
*p1=*p2;
*p2=temp;
}
main()
{
int a,b;
int *pointer_1,*pointer_2;
scanf("%d,%d",&a,&b);
pointer_1=&a;pointer_2=&b;
if(a<b) swap(pointer_1,pointer_2);
printf("\n%d,%d\n",a,b);
}

2.
swap(int *p1,int *p2)
{int *temp;
*temp=*p1;
*p1=*p2;
*p2=temp;
}

3.
main()
{ int *p1,*p2,*p,a,b;
scanf("%d,%d",&a,&b);
p1=&a;p2=&b;
if(a<b)
{p=p1;p1=p2;p2=p;}
printf("\na=%d,b=%d\n",a,b);
printf("max=%d,min=%d\n",*p1, *p2);
}

Answer 2

上面给了3个，我给第四个吧
只写简单的算法，具体代码你自己搞定吧
a,b
a=a^b;
b=a^b;
a=a^b;
这就OK了，中间那个符号是异或