Question

C#程序遍历数组A中所有元素（2钟方法）

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Answer 1

string[] A = new string[5] { "a1","a2","a3","a4","a5"};

//第一种方法

for (int i = 0; i < A.Length; i++)
{
Console.WriteLine(A[i]);
}

//第二种方法
IEnumerator e= A.GetEnumerator();
while (e.MoveNext())
{
Console.WriteLine(e.Current.ToString());
}

//第三种方法
foreach (string s in A)
{
Console.WriteLine(s);
}

Answer 2

很简单的啊，用for和foreach

Answer 3

很简单的啊，用for和foreach

Answer 4

遍历数组:
using System;
namespace Web
{
public class Test
{
public static void Print(int[][] arr)
{
if (arr != null)
{
for (int i = 0; i < arr.Length; i++)
{
for (int j = 0; j < arr[i].Length; j++)
{
Console.Write(arr[i][j] + " ");
}
Console.WriteLine();
}
}
}
public static void Main()
{
int[][] arr = new int[3][];
arr[0] = new int[]{1};
arr[1] = new int[]{2,3};
arr[2] = new int[]{4,5,6};
Print(arr);
}
}
}

运行结果:
1
2 3
4 5 6