
已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)
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(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)² *(x-y)=(2x+y)/(x-y)
x-3y=0,x=3y
(2x+y)/(x-y)=(6y+y)/(3y-y)=7/2
x-3y=0,x=3y
(2x+y)/(x-y)=(6y+y)/(3y-y)=7/2
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