Question

t^3-4t^2+3t-1=0

如何求解 结果？

Answer 1

用MATLAB可以求得它的3个解，
1个实数解，2个复数解，
t^3-4t^2+3t-1=0

>> syms t;
>> solve(t^3-4*t^2+3*t-1,t)

ans =

[ 1/6*(188+12*93^(1/2))^(1/3)+14/3/(188+12*93^(1/2))^(1/3)+4/3]
[ -1/12*(188+12*93^(1/2))^(1/3)-7/3/(188+12*93^(1/2))^(1/3)+4/3+1/2*i*3^(1/2)*(1/6*(188+12*93^(1/2))^(1/3)-14/3/(188+12*93^(1/2))^(1/3))]
[ -1/12*(188+12*93^(1/2))^(1/3)-7/3/(188+12*93^(1/2))^(1/3)+4/3-1/2*i*3^(1/2)*(1/6*(188+12*93^(1/2))^(1/3)-14/3/(188+12*93^(1/2))^(1/3))]

>> numeric(ans)

ans =

3.1479
0.4261 + 0.3690i
0.4261 - 0.3690i

>>