Question

C++ 实现复数加减运算

要求
1 采用重载“+”“-”运算符的方式；
2定义复数类，分别重载为类成员函数和友元函数的方式实现；
3在主函数中分别定义两个复数c1=6+3i;c2=3+6i,计算c1+c2,c1-c2,输出结果

Answer 1

#include "iostream.h"
class Complex
{
private:
double real,imag;
public:
Complex(double r,double i)
{
real=r;
imag=i;
}
/*friend Complex operator +(Complex& a,Complex& b)//友元运算符重载
{
double r=a.real+b.real;
double i=a.imag+b.imag;
return Complex(r,i);
}*/
Complex operator +(Complex&b)//类运算符重载
{
double r=real+b.real;
double i=imag+b.imag;
return Complex(r,i);
}
show()
{
cout<<real<<"+"<<imag<<"i";
}
};
void main()
{
Complex c1(6,3),c2(3,6),c=c1+c2;
c1.show();
cout<<"+";
c2.show();
cout<<"=";
c.show();
cout<<endl;

}
以上重载"+",重载"-"以此类似,仅供参考

Answer 2

给你弄了几行~
你照着写下去吧~
好久没有动手了~
#include <iostream.h>

class Complex{
public:
Complex(double r=0, double v=0):real(r),virt(v){}
friend Complex operator+(Complex a, Complex b);
friend ostream& operator<<(ostream& out, Complex& a);
private:
double real;
double virt;
};

ostream& operator<<(ostream& out, Complex& a){ return out <<a.real <<"+" <<a.virt <<"i\n"; }

Complex operator+(Complex a, Complex b)
{
return Complex(a.real+b.real, a.virt+b.virt);
}

void main()
{
Complex a(2,5), b(7,8), c(0,0);
c = a + b;
cout <<c;
c = 4.1 + a;
cout <<c;
c = b + 5.6;
cout <<c;
}

Answer 3

class complex
{
public:
    complex(double xx = 0.0, double yy = 0.0){x = xx;y = yy;}
    complex operator+(complex);
    complex operator-(complex);
    void display();
private:
    double x;
    double y;
};

complex complex::operator+(complex b)
{
    complex temp;
    temp.x = x+b.x;
    temp.y = y+b.y;
    return temp;
}

complex complex::operator-(complex b)
{
    complex temp;
    temp.x = x-b.x;
    temp.y = y-b.y;
    return temp;
}

void complex::display()
{
    cout<<"("<<x<<")"<<"+"<<"("<<y<<")"<<"j"<<endl;
}


void main()
{
    complex a(1.1, 1.2);
    complex b(2.1, 2.2);
    complex c;
    c = a+b;
    cout<<"a = ";
    a.display();
    cout<<"b = ";
    b.display();
    cout<<"c = a+b =";
    c.display();

    c = a-b;
    cout<<"c = a-b =";
    c.display();

}

Answer 4

http://zhidao.baidu.com/question/79347783.html?si=2楼主，这个应该符合你的要求。