Question

如何用java遍历出xml中每一个attributeValue的值

<?xml version="1.0" encoding="GB2312" standalone="yes"?>
<BroadcastData code="110000000" creationtime="20140315145420" version="2.0">
<ProviderInfo id="TVIBE" name="TVIBE" />
<SchedulerData type="PROGRAM">
<Channel>
<ChannelText language="chi">
<ChannelName>中央少儿</ChannelName>
</ChannelText>
<Event begintime="20140315003100" duration="005100" eventid="0" eventtype="00">
<EventText language="chi">
<Name>神探狄仁杰(25)</Name>
</EventText>
</Event>
<Event begintime="20140315012200" duration="003800" eventid="1" eventtype="11">
<EventText language="chi">
<Name>神探狄仁杰(26)</Name>
</EventText>
</Event>
<Event begintime="20140315020000" duration="020000" eventid="2" eventtype="11">
<EventText language="chi">
<Name>结束</Name>
</EventText>
</Event>
xml格式如上，如何能遍历出每一个Event中的begintime的值，我现在只能读取第一个，后面的就不知道怎么读了

Answer 1

递归读取法即可

package tool;

import java.util.Scanner;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NamedNodeMap;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class XMLTool
{
private static final String XML = "MyXml.xml";

private static Document getDoc ( String xml )
{
DocumentBuilderFactory dbf = null;
DocumentBuilder db = null;
Document doc = null;
try
{
dbf = DocumentBuilderFactory.newInstance ();
db = dbf.newDocumentBuilder ();
doc = null == xml ? db.newDocument () : db.parse (xml);
return doc;
}
catch (Exception e)
{
e.printStackTrace ();
}
return null;
}

private static void readXML ( String xml, String... looks )
{
Document doc = getDoc (xml);
recursionXML (doc, looks);
}

private static void recursionXML ( Node node, String... looks )
{
NodeList nl = node.getChildNodes ();
if (nl.getLength () == 0)
{
return;
}
for ( int i = 0; i < nl.getLength (); i++ )
{
Node n = nl.item (i);
Node parentNode = n.getParentNode ();
NamedNodeMap nnm = parentNode.getAttributes ();
if (
looks.length != 0
&&
parentNode.getNodeName ().equals (looks[0])
&&
nnm.getNamedItem (looks[1]).getNodeValue ().equals (looks[2])
)
{
System.out.println (nnm.getNamedItem ("Status"));
}
recursionXML (n, looks);
}
}

public static void main ( String[] args )
{
System.out.println ("输入id号进行查询: (n/N 退出)");
Scanner scanner = new Scanner (System.in);
String[] looks = { "UseTicketResult", "TicketNo", "47" };
String line = null;
while (scanner.hasNextLine ())
{
line = scanner.nextLine ().trim ();
if ("n".equalsIgnoreCase (line))
{
scanner.close ();
break;
}
looks[2] = line;
readXML (XML, looks);
System.out.println ("继续输入: ");
}
}
}

追问

这个异常怎么解决？还是我使用的不对？

追答

阁下怎么能直接使用我的代码呢，我的是特定xml的
recursionXML 是这个方法看通来就可以了

追问

给点注释，好让我知道哪些某些地方是做什么用的，我已经把文件名改成我自己的了，比如像String[] looks = { "Channel", "Event", "47" }三个值分别指什么，nnm.getNamedItem ("begintime")，还有这句，我的xml已经给出来了，麻烦大神帮我看看

追答

修改好了，看你这么辛苦，换下xml名字就可以直接运行了

追问

非常感谢你能帮我修改，不过还是报跟之前一样的异常，我是真不知道该怎么解决，能不能加我一下企鹅467810587.，我好详细的询问一下该怎么办

追答

怎么又报异常了啊，我用你的xml都可以运行出来的啊

图示：