Question

不等式应用题，急急！！！！！！！！！1

某出运站现有甲货物1530吨，乙货物有1150吨，安排用一列火车将这批火车运往目的地，这列火车可挂A、B两种不同规格的货箱50节。已知甲种货物35吨和乙种货物15吨可装满一节A货箱，甲种货物25吨和乙种货物35吨可装满一节B货箱，按此要求安排A、B两种货箱的节数，有哪几种运输方案？请设计出来。

Answer 1

解：设A种车箱x节,则B种车箱(50-x)节
35X+25(50-x)>=1530
15X+35(50-x)>=1150
解得：x>=28
x<=30
因为x为整数，所以x=28，29，30
50-28=22种
50-29=21种
50-30=20种
答:有3种运输方案
A种车箱28节,则B种车箱22节
A种车箱29节,则B种车箱21节
A种车箱30节,则B种车箱20节

Answer 2

设A种车箱X节,则B种车箱50-X节
35X+25(50-X)>=1530
X>=28
15X+35(50-X)>=1150
X<=30
答:3种,A种车箱28节,则B种车箱22节
A种车箱29节,则B种车箱21节
A种车箱30节,则B种车箱20节

Answer 3

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