先化简,再求值:(1a?2?1a+2)÷22?a,其中a=3-1
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(
?
)÷
=
÷
=
÷
=
×
=?
;
当a=
-1时,原式=?
=?
=?
1 |
a?2 |
1 |
a+2 |
2 |
2?a |
=
(a+2)?(a?2) |
(a?2)(a+2) |
2 |
2?a |
=
a+2?a+2 |
(a?2)(a+2) |
2 |
2?a |
=
4 |
(a?2)(a+2) |
2?a |
2 |
=?
2 |
a+2 |
当a=
3 |
2 | ||
|
2 | ||
|
2(
| ||||
(
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