Question

先化简，再求xx+1?x+3x?1?x2?2x+1x2+4x+3的值，其中x=32

先化简，再求xx+1?x+3x?1?x2?2x+1x2+4x+3的值，其中x=32．

Answer 1

原式=

x

x+1

-

x+3

x?1

?

(x?1)2

(x+1)(x+3)

=

x

x+1

-

x?1

x+1

=

x?x+1

x+1

=

1

x+1

，
当x=

3

2

时，原式=

1

3 2 +1

=

2

5

．