Question

2014荆州先化简再求值 (a2-b2/a2-2ab+b2+a/b-a)÷b2/a2-ab,

中a,b满足√a+

Answer 1

题目不完整，只化简
[(a²-b²)/(a²-2ab+b²)+a/(b-a)]÷b²/(a²-ab)
=[(a+b)(a-b)/(a-b)²-a/(a-b)]÷b²/a(a-b)
=[(a+b)/(a-b)-a/(a-b)]÷b²/a(a-b)
=[b/(a-b)]×a(a-b)/b²
=a/b。