Question

C语言 建立动态二维数组

我想建立一个n*n得数组，n由用户输入。请简单介绍一下如何引用。谢谢！

Answer 1

#include <stdio.h>
#include <malloc.h>

void main()
{
int i ,j;
int n;
int **a = (int**)malloc(sizeof(int*) * n);

scanf("%d", &n);

for(i = 0; i < n; i++)
{
a[i] = (int*)malloc(sizeof(int) *n);
if(a[i])
{
for( j = 0; j < n; j++)
{
scanf("%d", &a[i][j]);
}
}
}

for(i = 0; i < n; i++)
{
for( j = 0; j < n; j++)
{
printf("%d", a[i][j]);
}

}
}

Answer 2

#include <iostream>
using namespace std;

int main()
{
int n;
int **a;
scanf("%d", &n);
a = new int*[n];
for (int i = 0; i < n; i++)
a[i] = new int[n];

for (int i = 0; i < n; i++)
delete[] a[i];
delete[] a;

}