二重积分计算，麻烦过程写出来，谢谢 10
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∫-2u^2/(1-u^2)du
=∫(2-2u^2-2)/(1-u^2)du
=∫(2-2u^2)/(1-u^2)du-∫2/(1-u^2)du
=∫2du-∫[(1+u)+(1-u)]/(1-u^2)du
=∫2du-∫(1+u)/(1-u^2)+(1-u)/(1-u^2)du
=∫2du-∫1/(1-u)+1/(1+u)du
=∫2du-∫1/(1-u)du-∫l/(1+u)du
=∫(2-2u^2-2)/(1-u^2)du
=∫(2-2u^2)/(1-u^2)du-∫2/(1-u^2)du
=∫2du-∫[(1+u)+(1-u)]/(1-u^2)du
=∫2du-∫(1+u)/(1-u^2)+(1-u)/(1-u^2)du
=∫2du-∫1/(1-u)+1/(1+u)du
=∫2du-∫1/(1-u)du-∫l/(1+u)du
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这是随便粘贴过来的吗
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