Question

因式分解的数学题求解

因式分解的数学题求解如图

Answer 1

x-z=3............(1)
z-y=3...........(2)
(1)+(2)：x-y=6........(3)
x^2+y^2-2z^2
=(x^2-z^2)+(y^2-z^2)
=(x-z)(x+z)+(y-z)(y+z)
=3(x+z)-3(y+z)
=3(x+z-y-z)
=3(x-y)
=3×6
=18
注：^2——表示平拍橡方袭纤旁竖烂。

Answer 2

解：
因为：x-z=3 z-y=3
所以：仔答x-y=6，即 x²+y²稿拆=36+2xy---------①
x+y=2z，即 x²+y²=4z²-2xy-------②
由①和②得念敬慧：2(x²+y²)=36+4z²
所以：x²+y²-2z²=18

Answer 3

x^2 +y^2-2Z^2
=x^2-z^2 + y^2-z^2
=(x+z)(x-z)+(y+z)(y-z)
=3(x+z)-3(y+z)
=3(x－y) =18
注：x-z =3 和z-y =3, 二式相知虚此搭迅誉顷加，变成x－y=6

Answer 4

ok