Question

用matlab画散点图

我有一组1000*17的矩阵，每一行的1：16列是一个类的特征向量，17列是类别标记，怎样在二维的平面内画那个16维特征向量的散点图并且点的形状随17的不同而不同呢 谢谢啊！
给出矩阵前一部分数据
【 88, 92, 2, 99, 16, 66, 94, 37, 70, 0, 0, 24, 42, 65,100,100, 8
80,100, 18, 98, 60, 66,100, 29, 42, 0, 0, 23, 42, 61, 56, 98, 8
0, 94, 9, 57, 20, 19, 7, 0, 20, 36, 70, 68,100,100, 18, 92, 8
95, 82, 71,100, 27, 77, 77, 73,100, 80, 93, 42, 56, 13, 0, 0, 9
68,100, 6, 88, 47, 75, 87, 82, 85, 56,100, 29, 75, 6, 0, 0, 9
70,100,100, 97, 70, 81, 45, 65, 30, 49, 20, 33, 0, 16, 0, 0, 1
40,100, 0, 81, 15, 58,100, 57, 47, 87, 50, 88, 40, 42, 36, 0, 4
3, 71, 0, 95, 45,100,100, 99, 79, 78, 48, 53, 31, 24, 54, 0, 7
79, 87, 98, 81, 71,100, 72, 73,100, 66, 91, 21, 48, 0, 0, 13, 9
92, 95, 30,100, 34, 68, 87, 89, 84, 78,100, 35, 64, 0, 0, 19, 9】
就是这样的格式 主要我想体现多维数据在二维效果图上的可分性

Answer 1

应该用scatter函数吧

参考 网页链接

Answer 2

很简单啊！直接用plot函数就可以,如
plot(1,2,'or')%用o型红色显示
hold
on
plot(2,3,'ob')%用o型蓝色显示

Answer 3

A
=
load('C:\******\a.txt');
A1
=
A(A(:,3)
==
1,1:2);
A2
=
A(A(:,3)
==
2,1:2);
A3
=
A(A(:,3)
==
3,1:2);
plot(A1(:,1),A1(:,2),'r*',A2(:,1),A2(:,2),'bo',A3(:,1),A3(:,2),'g>')

Answer 4

假设有矩阵A，20行20列
然后
x=1:20;
[x,y]=meshgrid(x,x);
scatter(x(:),y(:),5,A(:))

Answer 5