Question

用switch语句编写一个计算器

高手的来啊..急救啊..

Answer 1

#include <stdio.h>
int main( )
{
double a, b;
char op;
scanf("%lf%c%lf", &a, &op, &b);
switch (op)
{
case '+':
printf("%lf + %lf = %lf\n", a, b, a + b);
break;
case '-':
printf("%lf - %lf = %lf\n", a, b, a - b);
break;
case '*':
printf("%lf * %lf = %lf\n", a, b, a * b);
break;
case '/':
if (b != 0)
printf("%lf / %lf = %lf\n", a, b, a / b);
else
printf("除数不能是0! \n");
break;
}
}

c语言

Answer 2

#include "stdio.h"
#include "math.h"
void main()
{float data1,data2;
char a;
printf("input:");
scanf("%f,%f,%c",&data1,&data2,&a);
switch (a)
{case '+':printf("%f%c%f=%f\n",data1,a,data2,data1+data2);break;
case '-':printf("%f%c%f=%f\n",data1,a,data2,data1-data2);break;
case '*':printf("%f%c%f=%f\n",data1,a,data2,data1*data2);break;
case '/':
{
if (data2==0)
{
printf("不存在\n");
}
else
{
printf("%f%c%f=%f\n",data1,a,data2,data1/data2);
}
}break;
default:printf("无结果\n");
}
}

这样就可以了 输入数据时间用,分开