Question

麻烦大佬解一下这道数学题？

帮忙解一下下面这道（底下过程应该是错的，还请大家不要参考），万分感谢！！！

Answer 1

强行拆开不就好了
拆开就是x^4-2ax^3+(4+a^2)x^2-4ax+4
所以a=3，c=4，b=13
结果为51

Answer 2

(x^2-ax+2)^2 =x^4-6x^3+bx^2-12x+c
To find: a(b+c)
solution:
(x^2-ax+2)^2
=x^4 +a^2.x^2 +4 +2(-ax^3-2ax +2x^2)
=x^4-2ax^3 +(a^2+4)x^2-4ax +4
≡x^4-6x^3+bx^2-12x+c
coef. of x^3
-2a=-6
a=3
coef. of x^2
a^2+4=b
b=9+4=13
coef. of constant
c=4
a(b+c)
=3(13+4)
=51